A train accelerated from 10 km/hr to 40km/hr in 2minutes.how much distance does it covers in this period? Assume that the tracks are straight?
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Answer:
7/6km
Explanation:
u=10km/h
=10×5/18
=25/3m/s
v=40km/h
=40×5/18
=100/9m/s
t=2min
=2×60
=120sec
a=v-u/t
=100/9-25/3/120
=5/216m/s2
S=v2-u2/2a
put the values
S=3500/3m
=7/6km
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