Question

a train accelerated from 10km/h to 40km/h in 2 min . how much distance does it cover in this period / assume the track is strait

Answer 1

Answer:

u = 10 km/h

v = 40 km/h

t = 2 min = 1/30 hr

Hence, a = (v-u)/t = 30 ÷ 1/30 = 900 km/h

s = ?

s = ut + 1/2at

=> s = (10 ×1/30) + (1/2 × 900 × 1/900)

=> s = 0.33 + 0.5 = 0.83 km or 830 m