A train accelerated from 10km/h to 40km/h in 2 min . how much distance does it cover in this period? Assume that the tracks are straight
Answers
Answer:
Your answer is 837.36 meters.
Explanation:
First, find acceleration using 1st equation of motion i.e: Vf = Vi + at
Then, find distance using 2nd equation of motion i.e: S = Vit + 1/2 at^2
Answer:
The distance covered by the train is about 172 metres.
Explanation:
Given:
Time t=2 minutes
Initial velocity = 10km/hr
Solution:
Let us convert km/hr into m/s
For the conversion multiply by to the initial velocity.
We get
=10×18/5
= 36 m/s
Similarly, convert the final velocity
Final velocity = 40 km/hr
=40×80/5
= 136 m/s
We have acceleration,
a=v–u/t
Substitute the values of u v and t in above expression
=136-36/2
=100/2
a=50m/s²
We have
=8=ut+1/2at²
=(36×2)+1/2×50×4
= 72+100
= 172 m
The train covers about 172 metres.