Physics, asked by marlapatitejaswi, 7 months ago

A train accelerated from 10km/hr to 40km/hr in 2 min. How much distance does it cover in this period ? Assume that the tracks are straight . plzzz kindly answer

Answers

Answered by rsagnik437
13

Correct question:-

A train accelerated from 10km/h to 40km/h in 2minutes.How much distance does the train cover in this period?Assume that the tracks are straight.

Given:-

•Initial velocity of the train(u)=10km/h

•Final velocity of the train(v)=40km/h

•Time taken=2mins

To find:-

•Distance covered by the train in given time.

Solution:-

At first,let us convert the speeds of the train into m/s and the time into seconds.

=>10km/h

=>10×5/18 (Since,1km/h=5/18 m/s)

=>50/18 m/s

=>40km/h

=>40×5/18

=>200/18 m/s

=>2mins=120 seconds. (Since,1min=60s)

From the 1st equation of motion:-

=>v=u+at

=>a=v-u/t

=>a=(200/18-50/18)/120

=>a=150/18/120

=>a=150/(18×120)

=>a=150/2160

=>a=5/72 m/s²

Hence,we have got the acceleration of the train as 5/72 m/s².

Now,from the 2nd equation of motion:-

=>s=ut+1/2at²

=>s=50/18×120+1/2×5/72×(120)²

=>s=6000/18+ (5/144)×14400

=>s=333.33+72000/144

=>s=333.33+500

=>s=833.33m or 0.83km

Thus,distance covered by the train is 833.33m or 0.83km.

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