A train accelerated from 10km/hr to 40km/hr in 2 minutes. How much
distance does it cover in this period
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initial velocity- 10km/hr=2.77m/s
final velocity- 40km/hr=11.11m/s
time- 2min= 120sec
a=?
using first equation of motion-
V=U+AT
a=v-u/t
a= 11.11-2.77/120
a= 0.07m/s^2
using third equation of motion and subtituting values we get-
v^2= u^2+2as
v^2-u^2= 2as
11.11^2-2.7^2=2*0.07*s
s=826.85m
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