Math, asked by barkhajain20, 11 months ago

A train accelerated from 10km/hr to 40km/hr in 2 minutes. How much
distance does it cover in this period

Answers

Answered by Anonymous
1

Answer:

⬇️ here is your answer-. ⬇️

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initial velocity- 10km/hr=2.77m/s

final velocity- 40km/hr=11.11m/s

time- 2min= 120sec

a=?

using first equation of motion-

V=U+AT

a=v-u/t

a= 11.11-2.77/120

a= 0.07m/s^2

using third equation of motion and subtituting values we get-

v^2= u^2+2as

v^2-u^2= 2as

11.11^2-2.7^2=2*0.07*s

s=826.85m

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