A train accelerated from 10km/hr to 40km/hr in 2 minutes. How much distance does it cover in this period? Assume that the tracks are straight?
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Answer :
It cover 172 m distance in this period
step by step explanation
initial velocity = 10km/hr = 10 × 18/5 = 36 m/s
final velocity = 40 km/hr = 40 × 18/5 = 136 m/s .
acceleration = v - u /t
= 136 - 36/2
= 100/2
= 50 m/s^2
s = ut + 1/2at^2
= 36 × 2 + 1/2 × 50 × 4
= 72 + 100
= 172 m
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