Question

A train
accelerated from 20 km/h to
80 km/h in 4minutes
how much distance
does it cover in this period
​

Answer 1

Answer:

$20kmph = 5.55ms \\ 80kmph = 22.22ms \\ 4minute = 4 \times 60 = 240s$

$v = u + at \\ 22.22 = 5.55 + a240 \\ a= 0.06ms ^{ - 2}$

${v}^{2} = {u}^{2} + 2as \\ 22.22 ^{2} = 5.55^{2} + 2 \times 0.06 \times s \\ s = 13.87m$