a train accelerated from 20 km / hard to 80 km / in 4 minutes how much distance does it cover in this period of some that the track a straight
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u=20x5/18=50/9m/s
v=80x5/18=200/9m/s
t=4 min= 240s
S=ut+½at²
=8000m or 8 km
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