A train accelerated from 20km/hr to 80km/hr in 4 minutes. How much distance does it cover in this period?
Answers
Answered by
5
a=v-u/t
=80-20/1/15
=60*15
=900kmph²
s=ut+at²/2
=20(1/15)+900(1/15)(1/15)/2
=4/3+2
=10/3km
hope helped!
=80-20/1/15
=60*15
=900kmph²
s=ut+at²/2
=20(1/15)+900(1/15)(1/15)/2
=4/3+2
=10/3km
hope helped!
takshtyagi44557:
thanks
Answered by
0
hi this is your answer\
using formula = v = u + at
a = v - u/t
a = 80 -20 /1/15
a = 60 /1/15
a = 60 mutiply 15
a = 900 km/h^2
now using formula s = ut + 1/2 at^2
s = 20 multiply 1/3 + 900 mutiply 1/15 multiply 1/15
now solve this u will get 4/3 km.
Thanx
harsh
using formula = v = u + at
a = v - u/t
a = 80 -20 /1/15
a = 60 /1/15
a = 60 mutiply 15
a = 900 km/h^2
now using formula s = ut + 1/2 at^2
s = 20 multiply 1/3 + 900 mutiply 1/15 multiply 1/15
now solve this u will get 4/3 km.
Thanx
harsh
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