Question

a train accelerated from 36 kilometre per hour in 10 seconds . 1.find acceleration .2 the distance travelled by car​

Answer 1

Explanation:

Given:

Initial velocity= 36km/h=36x5/18=10m/s

Final velocity =54km/h=54x5/18=15m/s

Time =10sec

Acceleration = v-u/ t

=15-10/10=5/10=1/2=0.5 m/s2

Distance =s=?

From second equation of motion:

S=ut +1/2 at^2

=10*10+1/2*0.5*10*10

=100+25

=125m

So distance travelled is 125m

you can put the correct number

Answer 2

Answer:

acceleration=v/t=(36*5/18)/10

=1 m/s^2

distance=v*t=(36*5/18)*10

=100m