Question

A train accelerated from10km/ hr to40 km/ hr in 2 min .how much distance does it cover in this period assume the teacks are straight

Answer 1

Answer:

initial velocity,u=10km/h

final velocity,v=40km/h

time,t=2min=1/30h

since , S=ut+1/2at^2

=10×1/30+(1/2)×(v-u/2)×(1/30)^2

=1/3+(1/2)×(30/2)×(1/900)

=1/3+1/120

=41/102 km/h^2

Explanation: