Question

A train accelerates from 10 metre per second to 20 metre per second in 20 second find the distance travelled by it

Answer 1

Explanation:

initial velocity (u) = 10 m/s

final velocity (v) = 20 m/s

time (t) =20 sec

acceleration (a) = (v-u) / t

a = (20-10) / 20

= 0.5 m/s^2

according to the third equation of motion

v^2 = u^2+2as ( s = distance)

(20)^2 = (10)^2 + (2)(0.5)(s)

400 = 100 + 1s

400 - 100 = s

300 = s

therefore distance (s) is 300m

Hope this is helpful!!!!

Answer 2

Answer:

Distance = 300 m

HOPE IT HELPS YOU