A train accelerates from 10m/s to 15m/s. Then find the acceleration and distance travelled by car.
Answers
Answered by
1
hello friend
ur query is incomplete ..u have not mention the time ..
m giving u the formula :
acceleration = final velocity - initial velocity / time
here initial velocity is 10m/s and final velocity is 15m/s
so, 15 m/s - 10m/s / t ( which u have not mention)
= 5 / t
and the answer will written as x m/s ²
hope u got me
ur query is incomplete ..u have not mention the time ..
m giving u the formula :
acceleration = final velocity - initial velocity / time
here initial velocity is 10m/s and final velocity is 15m/s
so, 15 m/s - 10m/s / t ( which u have not mention)
= 5 / t
and the answer will written as x m/s ²
hope u got me
PREMAN1:
if the time is 10 sec then and also u not given the distance
Answered by
4
Hello freind !!
Given -
Acceleration = ?
Distance travelled = ?
initial velocity , u = 10 m/s
Final velocity , v = 15 m/s
Time = 10 sec
we know
A = V- U / t
= 15 - 10 / 10
= 5 / 10
= 1/2 m/s^2
From 2nd eq of motion we have
s = ut + 1/2 at^2
= 10 ×10+ 1/2 ( 1/2 ) × 100
= 100 + 50 × 1/2
= 100 + 25
= 125 m
hence the distance travelled by the train is 125 m
please mark it as brainliest
Given -
Acceleration = ?
Distance travelled = ?
initial velocity , u = 10 m/s
Final velocity , v = 15 m/s
Time = 10 sec
we know
A = V- U / t
= 15 - 10 / 10
= 5 / 10
= 1/2 m/s^2
From 2nd eq of motion we have
s = ut + 1/2 at^2
= 10 ×10+ 1/2 ( 1/2 ) × 100
= 100 + 50 × 1/2
= 100 + 25
= 125 m
hence the distance travelled by the train is 125 m
please mark it as brainliest
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