Question

A train accelerates from 10ms^-1 to 20ms ^-1 in 20 sec. find the distance travelled by it

Answer 1

Answer:

acceleration= (20-10)/20 = 0.5 m/s^2

distance will be 300m

Answer 2

Answer:

Given

u = 10ms^-1

v = 20ms^-1

a = ?

t = 20 sec

s = ?

a = v - u/t

= 20 -10/20

= 10/20

= 1/2 = 0.5ms^-2

s = ut + 1/2at^2

= 10×20 + 1/2 × 0.5 × (20)^2

= 200 + 1/2 × 0.5 × 400

= 200 + 0.5 × 200

= 200 + 100

= 300m

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