A train accelerates from 10ms^-1 to 20ms ^-1 in 20 sec. find the distance travelled by it
Answers
Answered by
0
Answer:
acceleration= (20-10)/20 = 0.5 m/s^2
distance will be 300m
Answered by
0
Answer:
Given
u = 10ms^-1
v = 20ms^-1
a = ?
t = 20 sec
s = ?
a = v - u/t
= 20 -10/20
= 10/20
= 1/2 = 0.5ms^-2
s = ut + 1/2at^2
= 10×20 + 1/2 × 0.5 × (20)^2
= 200 + 1/2 × 0.5 × 400
= 200 + 0.5 × 200
= 200 + 100
= 300m
Plz mark the brainliest answer.....
Similar questions