Question

A train accelerates from 18km/hr to 36 km/hr in 5 minutes. Its acceleration in SI unit is
a. 1
b. 2
c. 3
d. 4

Answer 1

Answer:

Explanation:

Here initial velocity, u = 18 km/h = 18 * 5/18 = 5 m/s

Final velocity, v = 36 km/h = 36 * 5/18 = 10 m/s

Time, t = 5 mins = 5 * 60 = 300 seconds

Acceleration, a = (v - u)/t

a = (10 - 5)/300

a = 5/300

a = 1/60

a = 0.01 m/s^2

Answer 2

QUESTION:-

A train accelerates from 18 km/hr to 36 km/hr in 5 minutes. Its acceleration in SI unit is  

EXPLANATION:-

We know that,

$\sf\;1\;km/hr=\frac{5}{18}\;m/s\\\\36\;km/hr=36\times \frac{5}{18}\;m/s\\\\36\;km/hr=15\;m/s\\\\\\Similarily,\\18\;km/hr=10\;m/s$

so,

v=15 m/s

u=10 m/s

Time=5 minutes

Time=300 second

$\bf\;a=\frac{v-u}{t}$

a=(15-10)/(300)

a=5/300

a=1/60

So the acceleration will be:-

1/60 m/s²

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