Question

A train accelerates from 20m/s at 4m/s2 over a distance of 25.5m. What is the final
velocity of the train?

Answer 1

Answer:

Final velocity is 24.6 m/s.

Explanation:

Answer 2

Answer:

a = 4m/$s^{2}$

u = 20 m/s

s(Distance) = 25.5m

using 3rd eq of motion

2as=$v^{2}$-$u^{2}$

2x4x25.5=$v^{2}$-$20^{2}$

204=$v^{2}$-400

204+400=$v^{2}$

604=$v^{2}$

$\sqrt{604}$=v

24.57m/s=v

Explanation: