Question

. A train accelerates from 20m/s at 4m/s2 over a distance of 25.5m. What is the final velocity of the train?

Answer 1

Answer:

24.5 m/s

EXPLANATION:

U=INITIAL VELOCITY

V=FINAL VELOCITY

S= DISTANCE

a=acceleration

therefore,

V² = U² + 2as

V²= 20² + 2x4x25.5

V²=400 + 204

V²=604

=> V=√604

=> V=24.5 m/s (approximated)

hope it helps... thanks

Answer 2

Answer:

Final velocity= 24.58m/s

Explanation:

Given

u=20m/s

a=4m/s²

s=25.5

v²=u²+2as

v²=400+8×25.5

v= 24.58m/s

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