Question

A train accelerates from 36 kilometre are 254 kilometre are in 10 seconds find

Answer 1

Explanation:

Given:

Initial velocity= 36km/h-36x5/18=10m/s

Final velocity =54km/h-54x5/18=15m/s

Time =10sec

Acceleration = v-u/ t

-15-10/10=5/10-1/2-0.5 m/s2

Distance =s=?

From second equation of motion:

S=ut +1/2 at^2

=10*10+1/2*0.5*10*10

=100+25

=125m

So distance travelled is 125m