Question

A train Accelerates from 36 km/h in
10 sec, find its
a) acceleration
b) The distance
travelled, if it moves along a straight line. please give the full explanation
​

Answer 1

Answer:

The Distance is 360m and the Acceleration is 3.6 m/s²

Explanation:

Velocity = 36 km/hr

Time = 10 s

Acceleration = Velocity/Time

= a = 36/10 m/s²

= a = 3.6 m/s²

If the train moves in a straight line, Speed = Velocity,

Speed = Distance/Time

= 36 = D/10

= 360 m = Distance

Hope this helps.

Answer 2

$\color{darkblue}\underline{\underline{\sf Given-}}$

• Velocity of train (v) = 36km/h
• Time (t) = 10sec

$\underline{\sf Convert \: km/h \; into \: m/s}$

$\implies{\sf v= 36×\dfrac{5}{18} }$

$\color{orange}\implies{\sf v=10m/s}$

$\color{darkblue}\underline{\underline{\sf To \: Find-}}$

• Acceleration
• Distance

$\color{darkblue}\underline{\underline{\sf Solution-}}$

❏ Acceleration (a)

Rate of change of velocity is known as Acceleration.

$\color{violet}\bullet\underline{\boxed{\sf a=\dfrac{dv}{dt}}}$

$\implies{\sf a=\dfrac{10}{10}}$

$\color{red}\implies{\sf a=1\:m/s^2}$

❏ Distance (s)

From Newton's Second law of Motion

$\color{violet}\bullet\underline{\boxed{\sf s=ut+\dfrac{1}{2}at^2}}$

$\implies{\sf s=0+\dfrac{1}{2}×1×10×10 }$

$\color{red}\implies{\sf Distance (s)=50m }$

$\color{darkblue}\underline{\underline{\sf Answer-}}$

Acceleration of train is $\color{red}{\sf 1\:m/s^2}$

Distance of train travelled is $\color{red}{\sf 50\:m}$