Question

A train accelerates from 36 km/h to 54 km/h in 10 sec.

(i) Acceleration

(ii) The distance travelled by car.​

Answer 1

Hope it will help u...

thanks for asking....

Happy to help u.

and keep smiling always.....

things will be with u 4ever....

GOOD DAY AHEAD....TAKE CARE

Answer 2

u = 10 m^2

v = 15 m^2

acceleration = V- U /t = 5 /10 = 0.5 m^s^2

distance travel= s = ut+1/2at^2

= 10 × 10 + 1/2 ×0.5 × 100 = 125m

$<marquee>... acceleration = 0.5m^s^2 distance = 150 m ......$