Question

a train accelerates from 36 km/h to 54 km/h in 10 sec. (i) acceleration (ii) the distance travelled by car​

Answer 1

Answer :

Initial velocity = 36km/h = 10m/s

Final velocity = 54km/h = 15m/s

Time of journey = 10s

We have to find,

• Accelration of train
• Distance covered by train

✭ What is acceleration :

Acceleration is defined as the rate of change of velocity$.$

Mathematically, a = (v - u) / t

⇒ a = (v - u) / t

⇒ a = (15 - 10) / 10

⇒ a = 5/10

⇒ a = 0.5m/s²

✴ Distance travelled by train :

➝ v² - u² = 2as

➝ 15² - 10² = 2(0.5)s

➝ s = 225 - 100

➝ s = 125m

God Bless ☃

Answer 2

☕ Given :-

• Initial Velocity = 36km/h = 10m/s

• Final Velocity = 54km/h = 15m/s

• Time = 10 sec.

☕ To Find :-

• Acceleration.

• Distance Travelled.

☕ Solution :-

We know that,

$\bf\red{a = \dfrac{v - u}{t} }$

From This Formula Of Acceleration, We Can Find Acceleration.

Substitute The Values.

$\bf\green{a = \dfrac{15 - 10}{10} }$

$\bf\pink{a = 0.5 \: m {s}^{2} }$

Now, Calculating Distance.

We know the Second Equation Of Motion.

$\bf\purple{{v}^{2} - {u}^{2} = 2as}$

$\bf\orange{s = 225 - 100}$

$\bf\blue{s = 125m}$

So, Your Answers Are 0.5 ms² and 125 meters respectively.