Question

A train accelerates from 36 km/h to 54 km/h in 10 sec.
(i) Acceleration
(ii) The distance travelled by car.
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1. Answer 125 aana chahiye

Answer 1

Answer:

Initial speed u = 36 km/h = 36 x 1000/3600 m/s = 10 m/s Final speed v = 54 km/h = 54 x 1000/3600 m/s = 15 m/s Time t = 10 s Acceleration a = (v - u)/t = (15 - 10)/10 = 5/10 = 0.5 m/s2. Distance travelled S = ut + ½ at2 = 10 x 10 + ½ x 0.5 x 10 x 10 m = 100 + 25 = 125 m

Answer 2

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