A train accelerates from 36 km/h to 54 km/h in 10 sec.
(i) Acceleration
(ii) The distance travelled by car.
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(i)Change in velocity = 18 km/hr.= 5m/s.
Acceleration=(change in velocity/time)=(5/10)=0.5 m/s^2.(Ans.)
(ii)
S=ut+(1/2)*a*t^2
Therefore,
S=10*10+0.5*0.5*10^2
=125m
All the best!!!
Acceleration=(change in velocity/time)=(5/10)=0.5 m/s^2.(Ans.)
(ii)
S=ut+(1/2)*a*t^2
Therefore,
S=10*10+0.5*0.5*10^2
=125m
All the best!!!
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