a train accelerates from 36 km /h to 54 km/ h in 10 seconds ?calculate
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Hey friend
Here is your answer
u(initial velocity)=36km/h=(36×1000)/(60×60)=10m/s
v(final velocity) =54km/h=54000/3600=15m/s
t(time)=10s
a=(v-u) /t
a=(15-10)/10
a=5/10
a=0.2m/s²
Hope this helps you
Here is your answer
u(initial velocity)=36km/h=(36×1000)/(60×60)=10m/s
v(final velocity) =54km/h=54000/3600=15m/s
t(time)=10s
a=(v-u) /t
a=(15-10)/10
a=5/10
a=0.2m/s²
Hope this helps you
vishal741:
nice answer, correct
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