Question

A train accelerates from 36 km/h to 54 km/h in 10sec.find the acceleration and the distance travelled

Answer 1

Answer:

a= v-u/t

where v=54

u=36

t=10

a=54-36/10= 50.4m/sec.sq

and d=s/t

=50.4/10=5.04m/sec

Explanation:

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Answer 2

Explanation:

Given-

u=36m/s=36×5/18=10m/s

v=54m/s=54×5/18=15m/s

t=10sec

a=?

s=?

v=u+at

15=10+a×10

10a=15-10

a=5/10

a=0.5m/s^2

s=ut+1/2at^2

s=10×10+1/2×0.5×10×10

s=100+25

s=125m

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