A train accelerates from 36 km/h to 54 km/h in 10sec
(ii) The distance travelled by car.
i know the answer please tell me in the equation
s=ut+1/2 at^2
put value s=10 X 10 + 1/2 x O.5 X 10
PLEASE TELL ME WHYY 0.5 USE IN THE
PLEASE I WANT TO PREPARE FOR MY EXAMS
Answers
Answered by
1
Hope this helps you.
Thank you for your question.
Mark me as brainleist.
Attachments:
Answered by
6
Answer :-
Given :-
- Initial velocity = 36 km/hr
- Final velocity = 54 km/hr
- Time = 10 seconds
To Find :-
- Distance travelled
Solution :-
To find distance, we first need to find the acceleration of the body and then substitute the values in 2nd equation of motion.
- u = 36 km/hr = 36 × 5/18 = 10 m/s
- v = 54 km/hr = 54 × 5/18 = 15 m/s
- t = 10 s
→ v = u + at
→ 15 = 10 + 10 × a
→ 5 = 10a
→ a = 0.5
Acceleration = 0.5 m/s²
Substituting the value in 2nd equation of motion :-
→ s = ut + ½ at²
→ s = 10 × 10 + ½ × 0.5 × 10 × 10
→ s = 100 + 25
→ s = 125
Distance travelled = 125 m
Similar questions