Physics, asked by abhishek729189, 3 months ago

A train accelerates from 36 km/h to 54 km/h in 10sec
(ii) The distance travelled by car.

i know the answer please tell me in the equation

s=ut+1/2 at^2
put value s=10 X 10 + 1/2 x O.5 X 10
PLEASE TELL ME WHYY 0.5 USE IN THE
PLEASE I WANT TO PREPARE FOR MY EXAMS

Answers

Answered by kakarlanikhil108
1

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Answered by Anonymous
6

Answer :-

Given :-

  • Initial velocity = 36 km/hr
  • Final velocity = 54 km/hr
  • Time = 10 seconds

To Find :-

  • Distance travelled

Solution :-

To find distance, we first need to find the acceleration of the body and then substitute the values in 2nd equation of motion.

  • u = 36 km/hr = 36 × 5/18 = 10 m/s
  • v = 54 km/hr = 54 × 5/18 = 15 m/s
  • t = 10 s

→ v = u + at

→ 15 = 10 + 10 × a

→ 5 = 10a

→ a = 0.5

Acceleration = 0.5 m/s²

Substituting the value in 2nd equation of motion :-

→ s = ut + ½ at²

→ s = 10 × 10 + ½ × 0.5 × 10 × 10

→ s = 100 + 25

→ s = 125

Distance travelled = 125 m

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