Question

A train accelerates from 36 km/h to 54km/h in 10 secod calculate accleration

Answer 1

Answer:

0.5 m/s^2

Explanation:

Given :

Initial velocity = 36 km/h

$36 \frac{km}{h} = 36 \times \frac{5}{18} = 10 \: \frac{m}{s}$

Final velocity = 54 km/h

$54 \frac{km}{h} = 54 \times \frac{5}{18} = 15 \: \frac{m}{s}$

Time =10 seconds

To find:

Acceleration = a

Method 1

$a = \frac{v - u}{t}$

$a = \frac{15 - 10}{10}$

$a = \frac{5}{10}$

a = 0.5 m/s^2

Method 2

Using the first equation of motion = V=u+at

15= 10+10a

5=10a

a= 0.5 m/s^2

The train has an acceleration of 0.5m/s^2