Question

A train accelerates from 36 km/h to 54km/h in 10 seconds.

Find distance travelled by CAR​

Answer 1

Answer:= 0.5 m/s2.

Explanation:

Find a) Accelaration b) The distance travelled by a car​ Acceleration a = (v - u)/t = (15 - 10)/10 = 5/10 = 0.5 m/s2.

Answer 2

Answer:

125 m

Explanation:

u= 36 km/h or 10 m/s

v= 54 km/h or 15 m/s

t=10s

distance travelled = ?

acceleration=?

1:- v=u+at

15= 10+a(10)

5=10a

a=0.5 m/s²

2:- s=ut+1/2 at²

s= 100 + 1/2×50

2(0.5)(s)= 100 +25

s= 125 m