Question

A train accelerates from 36 km/hr to 54 km/hr in 10 second. find acceleration and the distance travelled by car​

Answer 1

Acceleration=(v-u)/t
So, (54-36) / 10
= 18/10
= 1.8

Answer 2

36×5/18=10m/s

54×5/18=15m/s

a=v-u/t

a=15-10/10

a=5/10=0.5m/s^2

2as=v^2-u^2

2×0.5×s=15^2-10^2

1×s =225-100

s=125/1=125m

please follow me