A train accelerates from 36 km per hour to 54 km per hour in use first one acceleration and second one the distance travelled by car
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Given :-
A train accelerates from 36 km per hour to 54 km per hour in 10 second.
To Find :-
1) acceleration
2) the distance traveled by car
Solution :-
We know that
1 km/h = 5/18 m/s
36 km/h = 36 × 5/18 = 10 m/s
54 km/h = 54 × 5/18 = 15 m/s
Now
①
We know that
a = (v - u)/t
a = (15 - 10)/10
a = 5/10
a = 0.5 m/s²
②
We know that
v² - u² = 2as
(15)² - (10)² = 2(0.5)(s)
225 - 100 = s
125 = s
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