Question

A train accelerates from 36km/h to 54 km/h in 10 sec.
a) Acceleration
b) The Distance Travelled by Car​

Answer 1

Answer:

Explanation:

Solution,

Here, we have

Initial velocity, u = 36 km/h = 36 × 5/18 = 10 m/s

Final velocity, v = 54 km/h = 54 × 5/18 = 15 m/s

Time taken, t = 10 seconds

To Find,

a. Acceleration, a = ?

b. Distance traveled, s = ?

We know that,

a = v - u/t

⇒ a = 15 - 10/10

⇒ a = 5/10

⇒ a = 1/2

⇒ a = 0.5 m/s²

Hence, the acceleration of train is 0.5 m/s².

According to the 3rd equation of motion,

We know that,

v² - u² = 2as

⇒ (15)² - (10)² = 2 × 0.5 × s

⇒ 225 - 100 = 1s

⇒ 125 = 1s

⇒ s = 125 m.

Hence, the distance traveled by train is 125 m.