Question

a train accelerates from 36km/h to 54 km/h in 10 seconds.find. acceleration ,speed of train​

Answer 1

☆Answer☆

initial velocity (u) = 36 km/hr or 10 m/s

final velocity (v) = 54 km/hr or 15 m/s

time (t) = 10 seconds

to find : acceleration and distance

here we go

solution : for acceleration

by using 1st equation of motion

v = u+at

15 = 10+10a

10a = 5

a = 0.5 m/s²

For Finding Distance :-

by using third equation of motion

v² = u²+2as

(15)² = (10)²+2*0.5*s

1s = 225-100

s = 125 meter

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