Question

A train accelerates from 36km/h to 54km/h in 10 sec.
Find the distance travelled by car.​

Answer 1

Explanation:

Find a) Accelaration b) The distance travelled by a car​ Acceleration a = (v - u)/t = (15 - 10)/10 = 5/10 = 0.5 m/s2.

Answer 2

Given : Initial Velocity (u) = 35 km/h = 10 m/s

            Final Velocity (v) = 54 km/h = 15 m/s

            Time(t) = 10 sec

To Find : Distance travelled (s)

Solutions :

$v = u + a*t$

$15 = 10 + 10a$

a = 0.5 $m/s^{2}$

$v^{2} - u^{2} = 2as$

$225 - 100 = 2*0.5*s$

$125 = s$

s = 125 m

Distance travelled by car is 125 m