Question

A train accelerates from 36km/h to 54km/h in 10sec find its acceleration and distance travelled by a train

Answer 1

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Answer 2

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➧ Initial speed u = 36 km/h

➾ 36 x 1000 / 3600 m/s
➾ 10 m/s 

➧ Final speed v => 54 km/h

➾ 54 x 1000 /3600 m/s
➾ 15 m/s

➧ Time => 10 s

➧ Acceleration a = (v - u) / t

➾ (15 - 10) / 10

➾ 5/10 = 0.5 m/s2

➧ Speed = ut + ½ at2

➾ 10 x 10 + ½ x 0.5 x 10 x 10m

➾ 100 + 25

➾ 125 m...✔

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