Question

a train accelerates from 36km/h to 54km/h in10sec

Answer 1

u(initial velocity)=36km/h=(36×1000)/(60×60)=10m/s

v(final velocity)=54km/h= 54000/3600=15m/s

t(time)=10s

a=(v-u) /t
a=(15-10)/10
a=5/10
a=1/2
a=0.5m/s²