Question

A train accelerates from 36km/h to54km/h in 10 sec find acceleration and distance traveled by the car assume motion of car is unifome

Answer 1

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$Using \\\\ V=u+at\\\:S=ut+\frac{1}{2}at^{2}\\ Where \\S=Distance\:Traveled \:by \:body\\u=initial \:velocity\\t=time \:\\a=acceleration\\V=final\:velocity$

$54\times (\frac{5}{18}) =36\times(\frac{5}{18}) +a(10)\\since \: velocity\:is \:given\:in\:km/hr\\\:hence\:we've\:to\:convert\:it \:into\:m/s\\15=10+10a\\10a=5\\a=0.5m/s^{2} \\\\\\Substituing\: value\: of\: this\: \bold{a}\: in\: second\: equation\: of\: motion\:\\S=10(10)+\frac{1}{2}0.5(10)^{2} \\S=100+25\\\red{S=125\\}$