Question

A train accelerates uniformly from 18 km h -¹ to 108 km h -¹ in 25 s. Calculate the
→ Acceleration.
→Distance covered. ​

Answer 1

$\huge\underline\pink{Question}$

A train accelerates uniformly from 18 km h -¹ to 108 km h -¹ in 25 s. Calculate the

→ Acceleration.

→Distance covered.

$\huge\underline\pink{Required\:Answer}$

→ Initial speed u = 18 km/hr = 18 × (5/18) = 5 m/s ;

Final speed v = 108 km/hr = 108 × (5/18) = 30 m/s

Acceleration a is calculated using the formula " v = u+at " , where t is time in seconds. Acceleration a = (v-u)/t = (30-5)/25 = 1 m/s2 Distance S is calculated using the equation S = u×t + (1/2)×a×t2 = 5×25 + (1/2)×1×25×25 = 437.5 m