Question

A train accelerates uniformly from 18 km/h to 36 km/h in 10 s. Find the distance traveled.

Answer 1

Answer:

u = 18 km/h = 18×5/18 = 5 m/s

v = 36 km/h = 36×5/18 = 10 m/s

t = 10 s

v = u+at

10 = 5 + 10a

10a = 10-5

10a = 5

a = 5/10

a = 0.5 m/s²

s = ut + 1/2at²

= 5×10+1/2×0.5×10²

= 50+0.25×100

= 50+25

= 75 m

Answer 2

Answer:

75 m

Explanation: