A train accelerates uniformly from 20 km/h to 72km/h in 20s . Find the distance travelled.
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20km/hr = 20 × 5/18 m/s = 50/9m/s
72km/hr = 72 × 5/18 = 20m/s
u = 50/9
v = 20
t = 20
a = (v - u)/t
a = (20 - 50/9)/20
a =( 180/9-50/9)/20
a = 130/9/20
a = 130×20/9
a = 260/9
s = ut + 1/2at²
s = 50/9 × 20 + 1/2 × 260/9 × 20²
s = 1000/9 + 130/9 × 400
=> s = 1000/9 + 52000/9
s = 53000/9 m
hope it helps dear friend ☺️✌️
72km/hr = 72 × 5/18 = 20m/s
u = 50/9
v = 20
t = 20
a = (v - u)/t
a = (20 - 50/9)/20
a =( 180/9-50/9)/20
a = 130/9/20
a = 130×20/9
a = 260/9
s = ut + 1/2at²
s = 50/9 × 20 + 1/2 × 260/9 × 20²
s = 1000/9 + 130/9 × 400
=> s = 1000/9 + 52000/9
s = 53000/9 m
hope it helps dear friend ☺️✌️
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