A train accelerates uniformly from 30 kilometre per hour to 60 km per hour and 30 seconds calculate the acceleration and the distance covered
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Answered by
1
36km/h = 10 m/s
72 km/h = 20 m/s
v = u +at
20 = 10 + a x 20
a = 1/2 m/s²
s = ut + 1/2at²
s= 10 x 20 + 1/2 x 1/2 x 20 x 20
s = 200 + 100
s = 300 m
so distance travelled = 300 m or 0.3 km
72 km/h = 20 m/s
v = u +at
20 = 10 + a x 20
a = 1/2 m/s²
s = ut + 1/2at²
s= 10 x 20 + 1/2 x 1/2 x 20 x 20
s = 200 + 100
s = 300 m
so distance travelled = 300 m or 0.3 km
Answered by
1
Answer:
HEY MATE!!
Explanation:
u=30km/hr=30*5/18=25/3 m/s
v=60km/hr=60*5/18=50/3 m/s
t=30sec
a=v-u/t
=50/3-25/3 / 30
=25/90=5/18m/s
distance=ut+a*t^2/2
=25/3 * 30 + 5/18 * 30 *30 /2
=250 + 125
=375m
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