Question

a train accelerates uniformly from 30km/h to 60km/h in 30 sec. find the distance covered by it during these 30 sec​

Answer 1

t = 30 s = 1/2 h

u = 30 km/h

v = 60 km/h

First we will find the acceleration so that we can put the values in the second equation of motion.

a = ∆v/∆t

a = (60-30) ÷ 1/2

a = (60-30) × 2

a = 60 km/h^2

Second equation of motion:

x = ut + 1/2at^2

=> x = (30)(1/2) + 1/2(60)(1/4)

=> x = 15 + 15/2

=> x = 45/2

=> x = 22.5 km