Question

A train accelerates uniformly from 30km/h yo 60km/h in 30 seconds. Calculate acceleration and distance covered

Answer 1

u=30km/hr=30*5/18=25/3 m/s
v=60km/hr=60*5/18=50/3 m/s
t=30sec
a=v-u/t
  =50/3-25/3 / 30
  =25/90=5/18m/s
distance=ut+a*t^2/2
             =25/3 * 30 + 5/18 * 30 *30 /2
             =250 + 125
              =375m

Answer 2

Answer:

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Explanation:

u=30km/hr=30*5/18=25/3 m/s

v=60km/hr=60*5/18=50/3 m/s

t=30sec

a=v-u/t

 =50/3-25/3 / 30

 =25/90=5/18m/s

distance=ut+a*t^2/2

            =25/3 * 30 + 5/18 * 30 *30 /2

            =250 + 125

             =375m