Question

A train accelerates uniformly from 36 kilometer per hour  to 72 kilometer per hour in 205 .
find the distance travelled by it.

Answer 1

u = 36 km/h = 36×5/18 = 10 m/s
v = 72 km/h = 72×5/18 = 20 m/s
t = 20 s
v = u+at
20 = 10 + 20a
20a = 20-10
20a = 10
a = 10/20
a = 1/2 m/s²
s = ut + 1/2at²
= 10×20+1/2×0.5×(20)²
= 200 + 1/2×1/2×400
= 200+100
= 300 m

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