Question

a train accelerates uniformly from 36 kilometre per hour to 72 kilometre per hour in 20 seconds find the distance travelled​

Answer 1

Answer:

Distance travelled is 1215 kms

Initial velocity u = 36

Final v = 72

time = 20sec

Explanation:

we know v= u+at

76=36+a(20)

36/20 = a

a= 1. 8

we also know

${v}^{2} - {u}^{2} = 2as$

${72}^{2} - {36}^{2} = 2(1.6)s$

3888/3.2 = s

S=1215 kms is the distance travelled by train.

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