Question

a train accelerates uniformly from 36 kilometre to 72 kilometre per hour in 20 seconds find the distance travelled by it​

Answer 1

u = 36 km/h = 10 m/s (36×1000/3600)

v = 72 km/h = 20 m/s (72×1000/3600)

t = 20s

a = $\frac{20-10}{20}$ = 0.5 ms^-2

s = ?

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Here, we will use the formula

$\boxed{\blue{v^{2}-u^{2} = 2as}}}$

20² - 10² = 2×0.5×s

400 - 100 = 1×s

300 = s

Hence, distance travelled = 300m :)

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