Question

a train accelerates uniformly from 36 km/h to 54 km/h in 10 mins. The acceleration is how much ??​

Answer 1

Answer:

18km/min

Step-by-step explanation:

(54-36)/10

(v-u)/t

Answer 2

Answer:

accelaration =v-u/t

here v=54km u=36km t=10 minutes

so

a=54km/h- 36km/h/10/60hours

we write 10/60beacuse

we have to convert min into hours

so 60 minutes =1hour

10minutes=10/60

54-36/10/60

18×60/10

1080/10=108 km/h^2 is the answer

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