Question

A train accelerates uniformly from 36 km/h
to 72 km/h in 10s. Find the distance
travelled.
(Ans. 150 m]​

Answer 1

Explanation:

initial speed = 36×5/18=10m/s

final speed =72×5/18=20m/s

time = 10s

acc= 20-10/10=1m/s^2

v^2-u^2=2as

so 400-100=2×1×s

300=2×s

s=150m