A train accelerates uniformly from 36 km/h to 72 km/h in 20 s.Find the distance travelled by it.
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Answered by
0
distance travelled is 36+72/2
=5.4
=5.4
Answered by
6
36 km/h = 10 m/s
72 km/h = 20 m/s
a = (v - u)/t
a = (20 - 10)/20
a = 0.5 m/s^2
S = ut + 0.5at^2
S = 10*20 + 0.5*0.5*20^2
S = 300 m
Distance travelled by it during this time interval is 300 m
72 km/h = 20 m/s
a = (v - u)/t
a = (20 - 10)/20
a = 0.5 m/s^2
S = ut + 0.5at^2
S = 10*20 + 0.5*0.5*20^2
S = 300 m
Distance travelled by it during this time interval is 300 m
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