A train accelerates uniformly from 36 km/h to 72 km/h in 20 s. Find the distance travelled.
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a=v - u
------
t
= 72 * 5/18 - 36 * 5/18
--------------------------
20
= 10/20
= 1/2 m/square
2aS = v sq. - u sq.
S = 400 - 100 = 300m
distance = 300 m
------
t
= 72 * 5/18 - 36 * 5/18
--------------------------
20
= 10/20
= 1/2 m/square
2aS = v sq. - u sq.
S = 400 - 100 = 300m
distance = 300 m
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