Question

A train accelerates uniformly from 36 km per hour to 72 km per hour in 20 seconds find the distance travelled by it

Answer 1

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Given :-

U = 36 km/h = 36×$\frac{1000m}{60 \times 60s}$ = 10m/s


V = 72 km/h = 72×$\frac{1000m}{60 \times 60s}$ = 20m/s


T = 20 s

A = ?

Find : Distance (S)


A = $\frac{V - U}{T}$


=》 $\frac{20 - 10}{20}$


=》 $\frac{10}{20}$


=》0.5 m/${s}^{2}$



To find distance let's use the Second Equation of Motion :


S = UT + $\frac{1}{2}$A${T}^{2}$



S = 10×20 + $\frac{1}{2}$0.5×${20}^{2}$



S = 200 + 100



S = 300 m



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Hope this helps . . . . . . . .☺☺